Finding absolute extrema on a closed interval (video) | Khan Academy
Use a graphing calculator to estimate the absolute maximum and absolute minimum values of the function, accurate to three decimal places. p(t) = \sqrt3{t^2 - t - 1},-1 \leq t \leq 3
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![SOLVED: Identify the intervals where f(x)=1/4 x^4+1/3 x^3-8x^2-16x is increasing and where decreasing on the interval [?4,4]. Then determine the relative extrema of ƒ(x). Lastly, determine the absolute extrema of ƒ(x).](https://cdn.numerade.com/previews/eee3baf0-7d30-4833-a431-258915dd0883_large.jpg "SOLVED: Identify the intervals where f(x)=1/4 x^4+1/3 x^3-8x^2-16x is increasing and where decreasing on the interval [?4,4]. Then determine the relative extrema of ƒ(x). Lastly, determine the absolute extrema of ƒ(x).")
SOLVED: Identify the intervals where f(x)=1/4 x^4+1/3 x^3-8x^2-16x is increasing and where decreasing on the interval [?4,4]. Then determine the relative extrema of ƒ(x). Lastly, determine the absolute extrema of ƒ(x).
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Use a graphing calculator to estimate the absolute maximum and absolute minimum values of the function, accurate to three decimal places. p(t) = \sqrt3{t^2 - t - 1},-1 \leq t \leq 3
![SOLVED: Graph each function on the indicated domain, and use the capabilities of your calculator to find the location and value of the absolute extrema. f(x)=(-5 x^4+2 x^3+3 x^2+9)/(x^4-x^3+x^2+7) ;[-1,1]](https://cdn.numerade.com/previews/94128dd9-bdd8-4412-ac96-5f82b3e9b72a_large.jpg "SOLVED: Graph each function on the indicated domain, and use the capabilities of your calculator to find the location and value of the absolute extrema. f(x)=(-5 x^4+2 x^3+3 x^2+9)/(x^4-x^3+x^2+7) ;[-1,1]")
SOLVED: Graph each function on the indicated domain, and use the capabilities of your calculator to find the location and value of the absolute extrema. f(x)=(-5 x^4+2 x^3+3 x^2+9)/(x^4-x^3+x^2+7) ;[-1,1]
